ANS:B - A perfect dam has been built by them across the river.

No answer description is available. 

ANS:B - False

No answer description is available. Let's discuss.

ANS:B - decimal

Decimal Range 0 to 9(0-9).
Totally 10 Digits.

Base depend on the number of total values Base 10 means ten distinct digits and that's possible only in decimal number system (deci means ten).

Base is the no.of total values. For decimal (0 to 9) total base is 10.

ANS:D - 10010111.11

The system work as below ( x2 increment -- divede 2 decrement).
0.25/2= 0.125
0.5/2 = 0.25
1/2 = 0.5
1
1x2 =2
2x2 = 4
4x2 = 8
8x2 = 16
16x2 = 32
32x2= 64
64x2=128.

128, 64, 32, 16, 8, 4,2,1 ---- 0.5, 0.25, 0.125.
So, 1 0 0 1 0 1 1 1 ---- 1 1 = Ans# 10010111.11.

ANS:C - 5A

Given (1011010) to the base 10.

Let's divide this binary number into four digits from last. i.e; 0101 1010
as there are only 7 numbers in the given binary form we are adding 0 in front just to make it even.

We have a rule called 8421. according to that;
The binary number 0101= 5 (4+1).
The binary number 1010=10 (8+2).
Then we get the hexadecimal number as 510 = 5A.
Answer= 5A.

ANS:B - 4

The reason is because a BCD should be able to represent all the digits (0-9).

The largest digit (9) needs for bits (1001). That's why 4 bits are needed for BCD.

ANS:C - stabilize the input analog signal during the conversion process

The sample and hold circuits are essentially used in linear systems. In some kinds of analog-to-digital converters, the input is often compared to a voltage generated internally from a digital-to-analog converter (D-A-C). The circuit tries a series of values and stops converting once the voltages are "the same" within some defined error margin. If the input value was permitted to change during this comparison process, the resulting conversion would be inaccurate and possibly completely unrelated to the true input value. Such successive approximation converters will often incorporate internal sample and hold circuitry. In addition, sample and hold circuits are often used when multiple samples need to be measured at the same time. Each value is sampled and held, using a common sample clock.

ANS:A - 1

Lets say a number given is 5. In binary, this is 101. The LSB is the first one from right while MSB is last one from right.

The weight is simply 2^n where n is the position of the '1' from the radix pt. In 101, it is not shown but it's after the right-most 1.

The weight of LSB 1 is 2^0 =1. Weight of MSB is 2^2 = 4.

ANS:A - Binary coding is pure binary.

Binary coding involves methods to code the numbers from decimal system into pure binary system. Whereas binary coded decimal system also has the 1s and 0s but only using specific weights assigned to the 4 bit-system used in it. In binary coded decimal we use the weights 8,4,2,1 to find out the bcd(binary coded decimal)of any digit. BCD system has only 0 to 9 as valid digits.

ANS:D - 9.125

Given (1001.0010)

To convert into a decimal number we need to multiply each binary digit with 2. As we move towards the left part of the decimal number the power of the 2 increases i.e; ( 2^0, 2^1, 2^2, 2^3......) as we move towards the right part of the decimal the power of 2 decreases i.e;( 2^-1, 2^-2, 2^-3)

So after multipying the binary digits with the number 2 we get 9.125.

In Detail: Given (1001.0010) , multiply each binary digit with 2 along with their powers. i.e;
2^3x1 + 2^2x0 +2^1x0 + 2^0x1 + 2^-1x0 + 2^-2x0 + 2^-3x1 +2^-4x0.
= 8 + 0 + 0 + 1 + 0 + 0 + 0.125 + 0 => 9.125.

Answer = D