ANS:D - Unholy

No answer description is available. 

ANS:C - stdio.h

stdio.h, which stands for "standard input/output header", is the header in the C standard library that contains macro definitions, constants, and declarations of functions and types used for various standard input and output operations.

ANS:A - True

No answer description is available.

ANS:C - a one will be added to the final result.

For Example, consider two 4-bit Numbers: A = 1100 and B = 1000; Cin =1 (as given).

Add A & B.
1100
1000
-------
10100

Now Cin added to the final result.
10100
-----1
--------
10101.

Hence, option C is correct.

ANS:C - Good documentation

No answer description is available

ANS:B - 00110    00101

Given:

01001 ->01001 -> 01001.

00011-> 1's Complement 11100.
And 2's Complement -> 11101.
Add Both the Numbers i.e 100110.

Ignore the MSB then we will get -> 00110.

Similarly,

01100 ->01100-> 01100.

00111 -> 1's Complement 11000
And 2's Complement ->11001
Add Both the Numbers i.e 100101.

And finally, we get -> 00101.

ANS:C - 1111 0011

11 in binary -> 0000 1011.

2's complement of (0000 1011) is 1111 0101(-11)

2 in binary -> 0000 0010.

2's complement of (0000 0010) is 1111 1110(-2).

Now Add 1111 0101(-11) and 1111 1110(-2)
1111 0101 (-11)
+ 1111 1110 (-2)
------------------------
11111 0011

So, the Answer of -11 + (-2) is 1111 0011.

ANS:C - 0001  1110    0100  1101    0101  1010

0b1010 = 0xA.
0b0011 = 0x3.
0xA * 0x3 = 0x1E = 0b00011110.

0b1011 = 0xB.
0b0111 = 0x7.
0xB * 0x7 = 0x4D = 0b01001101.

0b1001 = 0x9.
0b1010 = 0xA.
0x9 * 0xA = 0x5A = 0b01011010.

ANS:D - 0001  0001    0001  0101    0001  0111

Correction code is not always 6 it is only for 10-19. And why 6 then the answer is for 10 BCD is 0001_0000 which is 16 in decimal and BCD is sequence of binary numbers. For 20-29 12 is add and so on.

ANS:C - 61    3C    117

First find the decimal equivalent of 3C which will be = 3 * 16^1 + 12 * 16^0 i.e. 60.

Now find the decimal equivalent of 25 which will be= 2 * 16^1 + 5 * 16^0 i.e. 37.

Now add both these in the decimal form we get the decimal addition as= 60+37 i.e. 97.

Now convert this decimal 97 into hexadecimal format i.e. 61.

Now do the same for all.