Q1: A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:

ANS:A - 214

 4 | x            z = 6 x 1 + 4  = 10
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 5 | y -2         y = 5 x z + 3  = 5 x 10 + 3  = 53
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 6 | z - 3        x = 4 x y + 2  = 4 x 53 + 2  = 214
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   | 1 - 4
   
Hence, required number = 214.