Q1: (2² + 4² + 6² + ... + 20²) = ?

ANS:C - 1540

(2² + 4² + 6² + ... + 20²) = (1 x 2)² + (2 x 2)² + (2 x 3)² + ... + (2 x 10)² = (2² x 1²) + (2² x 2²) + (2² x 3²) + ... + (2² x 10²) = 2² x [1² + 2² + 3² + ... + 10²]

	Ref: (12 + 22 + 32 + ... + n2) =	1	n(n + 1)(2n + 1)
		6

=		4 x	1	x 10 x 11 x 21
			6

= (4 x 5 x 77) = 1540.