ANS:C -
1°43' 28"
The maximum deflection angle of a transition curve is given by the formula:
δ = L^2/6RL.
where:
L is the length of the transition curve.
R is the radius of the circular curve.
l is the length of the tangent.
In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:
δ = 90^2 / 6 * 500 * 90 = 1°43'08".
Therefore, the correct answer is 1°43'08".
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
L2/6RL.
500^2/(6*500*90)*(180).
=1'43'7.14".
