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Directions to Solve

In questions given below out of four alternatives, choose the one which can be substituted for the given word/sentence.

Q1: A child born after death of his father

A Progenitor

B Orphan

C Posthumous

D Bastard

Q2: Which of the following statement is correct about the program given below?

#include<iostream.h> 
int main()
{
    int x = 0;
    int &y = x; y = 5; 
    while(x <= 5)
    {
        cout<< y++ << ' ';
        x++;
    }
    cout<< x; 
    return 0; 
}

A The program will print the output 5 7.

B It will result in a compile time error.

C The program will print the output 5 6 7 8 9 10.

D The program will print the output 5 6 7 8 9 10 7.

Q3: An internal focussing type surveying telescope, may be focussed by the movement of

A convex-lens in the telescope

B concave lens in the telescope

C objective glass of the telescope

D plano-convex lens in the telescope.

Q4: Current through a charging capacitor exhibits

A a linear decay function

B an exponential growth function

C an exponential decay function

D a step decay function

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Q1: A child born after death of his father

Q2: Which of the following statement is correct about the program given below?
`#include<iostream.h> int main() { int x = 0; int &y = x; y = 5; while(x <= 5) { cout<< y++ << ' '; x++; } cout<< x; return 0; }`

Q3: An internal focussing type surveying telescope, may be focussed by the movement of

Q4: Current through a charging capacitor exhibits

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Q1: A child born after death of his father

Solution

Q2: Which of the following statement is correct about the program given below? #include<iostream.h> int main() { int x = 0; int &y = x; y = 5; while(x <= 5) { cout<< y++ << ' '; x++; } cout<< x; return 0; }

Solution

Q3: An internal focussing type surveying telescope, may be focussed by the movement of

Solution

Q4: Current through a charging capacitor exhibits

Solution

Q2: Which of the following statement is correct about the program given below?
`#include<iostream.h> int main() { int x = 0; int &y = x; y = 5; while(x <= 5) { cout<< y++ << ' '; x++; } cout<< x; return 0; }`