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Q1
:
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
A
1022
B
1032
C
1015
D
1008
Solution
ANS:
B
- 1015
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7 = 1008 + 7 = 1015
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