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Q1
:
x
b
(
b
+
c
-
a
)
.
x
c
(
c
+
a
-
b
)
.
x
a
(
a
+
b
-
c
)
= ?
x
c
x
a
x
b
A
x
abc
B
x
a
+
b
+
c
C
x
ab
+
bc
+
ca
D
1
Solution
ANS:
B
- 1
Given Exp.
=
x
(
b
-
c
)(
b
+
c
-
a
)
.
x
(
c
-
a
)(
c
+
a
-
b
)
.
x
(
a
-
b
)(
a
+
b
-
c
)
=
x
(
b
-
c
)(
b
+
c
) -
a
(
b
-
c
)
.
x
(
c
-
a
)(
c
+
a
) -
b
(
c
-
a
)
.
x
(
a
-
b
)(
a
+
b
) -
c
(
a
-
b
)
=
x
(
b
2
-
c
2
+
c
2
-
a
2
+
a
2
-
b
2
)
.
x
-
a
(
b
-
c
) -
b
(
c
-
a
) -
c
(
a
-
b
)
= (
x
0
x
x
0
)
= (1 x 1) = 1.
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