ANS:B - Only argument II is strong

Explanation: Making education free for all is not the only means to ensure literacy. An awareness needs to be aroused for this. So, argument I is vague. Also, such a step would require immense funds and lead to financial drain. So, argument II holds.

ANS:D - All of the above.

No answer description is available.

ANS:B - 15 cm lower

@M. Indravathi.

See when we take out a canal from a stream or river (parent channel) obviously we have to keep it at a lower level with respect to the parent channel so that water can easily enter into it. If we keep it at a higher elevation then proper entrance of water in the canal can not be achieved.

So, the given answer (B) is correct.

ANS:C - a standing wave which is not progressing

No answer description is available.

ANS:D - F8

No answer description is available.

ANS:D - High viscosity index means a large change in viscosity with change in temperature.

The wrong statement among the options provided is: Naphthenic oil has very low viscosity index. Here's why:

• Multigrade lubricating oils have high viscosity index: This statement is generally true. Multigrade oils are formulated to have a high viscosity index, which means their viscosity changes less with temperature compared to single-grade oils.
• Paraffinic oil has very high viscosity index: Paraffinic oils typically have a higher viscosity index than naphthenic oils. This is because paraffinic oils contain straight-chain or branched-chain hydrocarbons that have a more uniform molecular structure, resulting in less change in viscosity with temperature.
• Naphthenic oil has very low viscosity index: This statement is incorrect. Naphthenic oils actually tend to have a higher viscosity index than paraffinic oils. Naphthenic oils contain cyclic hydrocarbons (naphthenes) that can vary in structure, but they generally have better viscosity-temperature behavior compared to paraffinic oils.
• High viscosity index means a large change in viscosity with change in temperature: This statement is incorrect. High viscosity index actually means a smaller change in viscosity with temperature. Oils with high viscosity index maintain their viscosity more consistently across a range of temperatures, whereas oils with low viscosity index experience greater changes in viscosity with temperature.

ANS:C - China

China is building a dam on the Mabja Zangbo river near the Indian border.

ANS:A - A:15 B:38

Structure of the Pattern:

• There are two ovals with distinct patterns based on the properties of the numbers they contain.
• Oval A contains Prime Numbers.
• Oval B contains Square Numbers.

Explanation of the Pattern:

1. Oval A (Prime Numbers):
   • Prime numbers are integers greater than 1 that have no positive divisors other than 1 and themselves.
   • For example, the prime numbers between 1 and 15 include: 2, 3, 5, 7, 11, 13.
   • The sum of these prime numbers or a specific property related to the number 15 might fit within this pattern.
2. Oval B (Square Numbers):
   • Square numbers are integers that are the square of another integer.
   • For example, the square numbers up to 38 include: 1, 4, 9, 16, 25, 36.
   • The number 38 could relate to the count of square numbers up to that value or a specific property of these numbers.

Example Calculation:

1. For Oval A (Prime Numbers):
   • Let's assume you have the following prime numbers: 2, 3, 5, 7, 11, 13.
   • The number 15 could represent the total count of distinct prime numbers within a certain range or a specific property related to these numbers.
2. For Oval B (Square Numbers):
   • Square numbers less than or equal to 38 are: 1, 4, 9, 16, 25, 36.
   • The number 38 could be related to the maximum value where the square numbers are listed or a property involving these numbers.

Conclusion:

• Oval A: Contains prime numbers, and the number 15 might be related to a specific property or total count of such numbers within a certain range.
• Oval B: Contains square numbers, and the number 38 likely relates to the maximum value up to which square numbers are considered or a related property.

ANS:C - 3

Structure of the Pattern:

• There are three ovals arranged such that there is a central oval and two other ovals on the left and right.
• The number in the central oval is calculated based on the numbers in the left and right ovals.

Explanation of the Pattern:

1. Identify the Numbers:
   • Note the numbers in the left and right ovals.
2. Apply the Calculation:
   • Sum the numbers from the left and right ovals.
   • Divide the result by 3 to determine the number in the central oval.

Step-by-Step Process:

1. Sum the Numbers:
   • Add the number from the left oval to the number from the right oval.
2. Divide by 3:
   • Take the sum calculated in the previous step and divide it by 3.

Example Walkthrough:

• Left Oval: 6
• Right Oval: 9

Calculation:

1. Sum the Numbers: 6+9=156 + 9 = 156+9=15
2. Divide by 3: 153=5\frac{15}{3} = 5315​=5

• Desired Sum: 3×3=93 \times 3 = 93×3=9

• Example Numbers:
  • Left Oval: 4
  • Right Oval: 5

Verification:

1. Sum the Numbers: 4+5=94 + 5 = 94+5=9
2. Divide by 3: 93=3\frac{9}{3} = 339​=3

Conclusion:

ANS:C - 7

Structure of the Pattern:

• There is a circle divided into segments, with each segment having a specific value.
• Each segment's value is calculated based on numbers from segments directly opposite to it.

Explanation of the Pattern:

1. Identify Numbers:
   • Each segment has two outer numbers (from opposite segments) and an inner grey segment.
2. Apply the Calculation:
   • Multiply the two outer numbers from one segment.
   • Subtract the sum of the two outer numbers from the opposite segment.
   • The result gives the value for the inner grey segment.

Step-by-Step Process:

1. Identify Outer Numbers:
   • For a segment, determine the numbers in the two outer segments directly opposite to it.
2. Calculate the Value:
   • Multiply the outer numbers together.
   • Subtract the sum of the outer numbers from the opposite segment.
   • The result is the value for the inner grey segment.

Example Walkthrough:

• Segment 1 (Opposite to Grey): Outer numbers are 4 and 5.
• Segment 2 (Grey Segment): We need to calculate this value.

1. Multiply Outer Numbers of Segment 1: 4×5=204 \times 5 = 204×5=20
2. Identify the Sum of Outer Numbers in the Opposite Segment (Segment 2):
   • Assume outer numbers in Segment 2 are 6 and 7.
   6+7=136 + 7 = 136+7=13
3. Subtract the Sum from the Product: 20−13=720 - 13 = 720−13=7

Conclusion: