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Arithmetic Reasoning

Q1: A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

A 9, 46

B 9, 50

C 10, 46

D 10, 50

ANS:B - 9, 50

Explanation: We have : A = 3B ...(i) and C - 4 = 2 (A - 4) ...(ii) Also, A + 4 = 31 or A= 31-4 = 27. Putting A = 27 in (i), we get: B = 9. Putting A = 27 in (ii), we get C = 50.



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