Q1: Nitin's age was equal to square of some number last year and the following year it would be cube of a number. If again Nitin's age has to be equal to the cube of some number, then for how long he will have to wait?

ANS:B - 38 years

Explanation: Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube. Such numbers are 25 and 27. Thus, Nitin is now 26 years old. Since the next perfect cube after 27 is 64, so required time period = (64 - 26) years = 38 years.