Q1: What will be the output of the program?

#include<stdio.h>
int func1(int);

int main()
{
    int k=35;
    k = func1(k=func1(k=func1(k)));
    printf("k=%d\n", k);
    return 0;
}
int func1(int k)
{
    k++;
    return k;
}

ANS:D - k=38

Step 1: int k=35; The variable k is declared as an integer type and initialized to 35. Step 2: k = func1(k=func1(k=func1(k))); The func1(k) increement the value of k by 1 and return it. Here the func1(k) is called 3 times. Hence it increements value of k = 35 to 38. The result is stored in the variable k = 38. Step 3: printf("k=%d\n", k); It prints the value of variable k "38".