[Solved] Point out the error in the program #include<stdio.h> int main() { int a=10; void f(); a = f(); printf( %d\n , a); return 0; } void f() { printf( Hi ); } - Programming - C Programming - Functions

Functions

Q1: Point out the error in the program

#include<stdio.h>

int main()
{
    int a=10;
    void f();
    a = f();
    printf("%d\n", a);
    return 0;
}
void f()
{
    printf("Hi");
}

A Error: Not allowed assignment

B Error: Doesn't print anything

C No error

D None of above

ANS:A - Error: Not allowed assignment

The function void f() is not visible to the compiler while going through main() function. So we have to declare this prototype void f(); before to main() function. This kind of error will not occur in modern compilers.

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Functions

Q1: Point out the error in the program
`#include<stdio.h> int main() { int a=10; void f(); a = f(); printf("%d\n", a); return 0; } void f() { printf("Hi"); }`

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Mcqs Questions

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Functions

Q1: Point out the error in the program #include<stdio.h> int main() { int a=10; void f(); a = f(); printf("%d\n", a); return 0; } void f() { printf("Hi"); }

Solution

For help Students Orientation Mcqs Questions

Q1: Point out the error in the program
`#include<stdio.h> int main() { int a=10; void f(); a = f(); printf("%d\n", a); return 0; } void f() { printf("Hi"); }`

For help Students Orientation
Mcqs Questions