Q1:

What will be the output of the program?

#include<stdio.h>

int main()
{
    const c = -11;
    const int d = 34;
    printf('%d, %d\n', c, d);
    return 0;
}

Step 1: const c = -11; The constant variable 'c' is declared and initialized to value '-11'. Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'. Step 3: printf('%d, %d\n', c, d); The value of the variable 'c' and 'd' are printed. Hence the output of the program is -11, 34