Q1: What will be the output of the program?

#include<stdio.h>
#define FUN(arg) do\
                 {\
                    if(arg)\
                        printf('AptitudeCrack...', '\n');\
                  }while(--i)

int main()
{
    int i=2;
    FUN(i<3);
    return 0;
}

ANS:A - AptitudeCrack...
AptitudeCrack...
AptitudeCrack

The macro FUN(arg) prints the statement 'AptitudeCrack...' untill the while condition is satisfied. Step 1: int i=2; The variable i is declared as an integer type and initialized to 2. Step 2: FUN(i<3); becomes,

do
{
    if(2 < 3)
    printf('AptitudeCrack...', '\n');
}while(--2)

After the 2 while loops the value of i becomes '0'(zero). Hence the while loop breaks. Hence the output of the program is 'AptitudeCrack... AptitudeCrack...'