Q1: What will be the output of the program if the array begins 1200 in memory?

#include<stdio.h>

int main()
{
    int arr[]={2, 3, 4, 1, 6};
    printf('%u, %u, %u\n', arr, &arr[0], &arr);
    return 0;
}

ANS:A - 1200, 1202, 1204

Step 1: int arr[]={2, 3, 4, 1, 6}; The variable arr is declared as an integer array and initialized. Step 2: printf('%u, %u, %u\n', arr, &arr[0], &arr); Here, The base address of the array is 1200. => arr, &arr is pointing to the base address of the array arr. => &arr[0] is pointing to the address of the first element array arr. (ie. base address) Hence the output of the program is 1200, 1200, 1200