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Applied Mechanics

Q1: If the tension in a cable supporting a lift moving upwards is twice the tension when the lift is movng downwards, the acceleration of the lift, is

A

B

C

D

ANS:B -

Upward tension = m(g+a)
here given downward tension = 2t = m(g-a).
t = 2m(g-a) = m(g+a)
= 2mg + ma = mg - ma
= mg = 3ma.
g = 3a.
a = g/3.



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