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Applied Mechanics

Q1: A bullet weighing 200 g is fired horizontally with a velocity of 25 m/sec from a gun carried on a carriage which together with the gun weighs 100 kg. The velocity of recoil of the gun, will be

A 0.01 m/sec

B 0.05 m/sec

C 1.00 m/sec

D 1.5 m/see.

ANS:B - 0.05 m/sec

MV=mv Where, Gun of mass (M)=100kg, fired velocity (v)= 25m/s, bullet mass (m)=200gm =0.2 kg.

So, V=mv/M.

V= (0.2*25)/100 =0.05m/s.



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