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Digital Electronics

Q1:
The Boolean expression for the circuit of the given figure

A A {F + (B + C) (D + E)}

B A [F + (B + C) (DE)]

C A + F + (B + C) (D + E)]

D A [F + (BC) (DE)]

ANS:A - A {F + (B + C) (D + E)}

B and C in parallel give B + C. Similarly D and E in parallel give D + E. (B + C) in series with (D + E) give (B + C) (D + E). Since F is in parallel we get F + (B + C) (D + E). Finally A is in series. Therefore we get A[F + (B + C) (D + E)].



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