Fluid Mechanics

Q1:

For turbulent fluid flow in pipe, the expression for Prandtl one seventh power law is (where, r= pipe radius, x = distance).

A V/Vmax = (x/r)1/7

B V/Vmax = (r/x)1/7

C V/Vmax = (x.r)1/7

D none of these

ANS:A - V/Vmax = (x/r)1/7

For turbulent fluid flow in a pipe, the expression for Prandtl's one-seventh power law relating the velocity VVV at distance xxx from the pipe wall to the maximum velocity VmaxV_{\text{max}}Vmax​ is: VVmax=(xr)1/7\frac{V}{V_{\text{max}}} = \left( \frac{x}{r} \right)^{1/7}Vmax​V​=(rx​)1/7

Explanation:

  1. Prandtl's One-Seventh Power Law:
    • Prandtl's one-seventh power law describes the radial velocity profile in fully developed turbulent flow in a pipe.
    • According to this law, the velocity VVV at a distance xxx from the centerline (where rrr is the pipe radius) varies with the seventh root of the radial distance xxx.
    • This means that as you move away from the centerline towards the pipe wall, the velocity decreases following a power law relationship.
  2. Options Analysis:
    • VVmax=(xr)1/7\frac{V}{V_{\text{max}}} = \left( \frac{x}{r} \right)^{1/7}Vmax​V​=(rx​)1/7: This correctly represents Prandtl's one-seventh power law, where xxx is the radial distance from the pipe centerline and rrr is the pipe radius.
    • VVmax=(rx)1/7\frac{V}{V_{\text{max}}} = \left( \frac{r}{x} \right)^{1/7}Vmax​V​=(xr​)1/7: This would describe an inverse relationship, which is not consistent with Prandtl's law.
    • VVmax=(x⋅r)1/7\frac{V}{V_{\text{max}}} = \left( x \cdot r \right)^{1/7}Vmax​V​=(x⋅r)1/7: This would imply a multiplication, which is not the form of Prandtl's law.
    • None of these: This option is incorrect because the correct form of Prandtl's one-seventh power law is represented by the first option.

Conclusion:

Therefore, the correct expression for Prandtl's one-seventh power law for turbulent fluid flow in a pipe is: VVmax=(xr)1/7\frac{V}{V_{\text{max}}} = \left( \frac{x}{r} \right)^{1/7}Vmax​V​=(rx​)1/7



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