Q1: The smallest 5 digit number exactly divisible by 41 is:

ANS:B - 10004

The smallest 5-digit number = 10000.

 41) 10000 (243
     82
     ---
     180
     164
     ----
      160
      123
      ---
       37
      --- 

 Required number = 10000 + (41 - 37)
                 = 10004.