

Numbers - General Aptitude
Q1: The smallest 5 digit number exactly divisible by 41 is:A 1004
B 10004
C 10045
D 10025
E
None of these
ANS:B - 10004 The smallest 5-digit number = 10000. 41) 10000 (243 82 --- 180 164 ---- 160 123 --- 37 --- Required number = 10000 + (41 - 37) = 10004. |


For help Students Orientation
Mcqs Questions
One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.