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Directions to Solve
In the following questions choose the word which is the exact OPPOSITE of the given words.
ANS:D - Stale
No answer description is available.
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C Pin 8 should be pulsing.
ANS:D - no problem
Ic 7451 is a 14 pin IC, pin 7 is GND & pin 14 is Vcc. So here vcc is applied then ic is in on state & now the 2 and gates have 1, 2, 4, 5 as inputs &6 as output pin & another gate has 13, 12, 10, 9 as inputs and 8 as output.
Here given that;
1-on, 2-changing, 4, 5 -on, so output pin 6 depends on only input 2.
10th pin is in the off state so we can get 8 pin always off, by this we can say that there is no need to change the conditions all are correct.
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ANS:A - 1
For 3-input AND Gate: The output Y = A * B * C
A B C Y
0 0 0 0
0 0 1 0
0 1 0 0
0 1 1 0
1 0 0 0
1 0 1 0
1 1 0 0
1 1 1 1 <== On this case only the output will be HIGH.
Therefore, the answer is 1 possibility.
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ANS:B - X = ABC
As per the question 3 inputs so the inputs be A, B and C then according to AND gate it is defines the product so for this three inputs it is X=ABC.
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B less power than a TTL IC
C the same power as a TTL IC
D more power than a TTL IC
ANS:A - less power than a TTL IC
I'm not sure about how much volt it ll consume but its definetly less than that of TTL opponent because CMOS circuits are less likely to produce power supply transients when switching between states. The transition level between high and low logic states is usually half the supply voltage, which means CMOS has superior noise immunity to TTL.
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B The output is inverted.
ANS:C - The output is inverted.
Already NAND gate is the inversion of AND gate and the small on the output indicates the NOT gate operation and thus the output is the inverted form.
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ANS:C - 3, 6, 8, and 11
7432 is a 14 pin IC is an OR gate.
Pin Description
1 A Input Gate 1
2 B Input Gate 1
3 Y Output Gate 1
4 A Input Gate 2
5 B Input Gate 2
6 Y Output Gate 2
7 Ground
8 Y Output Gate 3
9 A Input Gate 3
10 B Input Gate 3
11 Y Output Gate 4
12 A Input Gate 4
13 B Input Gate 4
14 Positive Supply
So 3, 6, 8, 11 are output pins for OR gate.
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B power is removed from the gate's IC
C power is applied to the gate's IC
ANS:A - the input is LOW
If input is zero (low) then output will be 1 (high). Because NOT gate perfoms invert operation.
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B
ANS:B -
because it is the invertion of the input
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