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Directions to Solve
In the following questions choose the word which is the exact OPPOSITE of the given words.
ANS:B - Honest
No answer description is available.
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A Enable must be active for 6  s.
B Enable must be active for 12  s.
C Enable must be active for 3  s.
D Enable must be active for 0  s.
ANS:C - Enable must be active for 6 s.
1 pulse dosen't mean a positive half part.
It means a complete period of pulse. So if output needs 6 pulses the enable need to be active for 6 times i.e 6*1us.
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D enable or disable, enable or disable
ANS:C - enable or disable, enable or disable
OR AND both can give out low output and high output so it can be used as a switch.
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A not sensitive to electrostatic discharge
ANS:B - not sensitive to electrostatic discharge
In TTL the conduction is only due to charge carriers (i.e. , holes and electrons) but not with electrostatic field elements like FET.
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ANS:B - negative-AND gate
In this problem we can solve like also,
At first we have taken 2 input as 1 & 0. In the nor gate the output is 0.
It is equivalent to negative and gate because in and gate we will got 0 as output. So in negative and gate it must be 1.
Hence 2 input-nor gate is equivalent to negative and gate.
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ANS:C - 7
Let there are three inputs a,b,c so truth table for the three input has 8 possibilties.
a b c o/p
0 0 0 0
0 0 1 1
0 1 0 1
0 1 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 1 1 1
this is the truth table for or gate
and output(o/p) of or gate is a+b+c.
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ANS:D - unit loads
The maximum fan-out of an output measures its load-driving capability: it is the greatest number of inputs of gates of the same type to which the output can be safely connected.
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ANS:C - 64
The truth table formula is 2^n .
n= number of varriable .
For example : 6 input variable.
2^6=64.
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ANS:C - 7408
7400 - NAND,
7402 - NOR,
7404 - NOT,
7408 - AND,
7432 - OR,
7486 - XOR.
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