|
Directions to Solve
In the following questions choose the word which is the exact OPPOSITE of the given words.
ANS:C - Discourteous
No answer description is available.
|
ANS:B - No
Every actual argument list must be known at compile time. In that sense it is not truly a variable argument list.
|
ANS:C - 3
Question is asking about how many and gate required. For this expression 3 AND gate 1 OR gate and 3 Inverters is required.
|
ANS:B - 2
No answer description is available
|
ANS:A - 1
The inverter can be produced with single (1) NAND gate, because we can tie (combine) both the inputs of the NAND gate together and make it single. It works as a inveter.
|
A A = 0, B = 0, C = 1, D = 1
B A = 1, B = 1, C = 0, D = 0
C A = 1, B = 1, C = 1, D = 1
D A = 1, B = 0, C = 1, D = 0
ANS:D - A = 1, B = 0, C = 1, D = 0
A AND with B.
C AND with D.
Output of first AND gate AB is OR with output of second AND gate is CD.
So, output of OR gate is,
Y= AB+CD.
So, A=1, B=0, C=1, D=0.
AB=0, CD=0.
So Output Y=0.
Option D is the write Answer.
|
A A = 0, B = 0, C = 0, D = 0
B A = 0, B = 1, C = 1, D = 0
C A = 1, B = 1, C = 0, D = 0
D A = 1, B = 0, C = 0, D = 0
ANS:C - A = 1, B = 1, C = 0, D = 0
Put all combination into two AND gates with One OR gate. In one combition you will get 1 as output. You will get option C as answer.
|
ANS:B - (B)
In option B C NAND D = CD'.
Before OR it is inverted so input to or gate is CD and A' and B'. So that's why o/p= (A'+B'+CD).
|
ANS:A - 2-input AND gate
SANJIYAsaid: 1 decade ago
B waveform is One ON(1).
A waveform is three ON(3).
3*1=3 using and gate.
The output waveform X is a multiplication of A and B.
|
A three AND gates, one OR gate
B three AND gates, one NOT gate, one OR gate
C three AND gates, one NOT gate, three OR gates
D three AND gates, three OR gates
ANS:B - three AND gates, one NOT gate, one OR gate
AB=1 AND gate.
ABC=1 AND gate (get AB from output above then and to C),
AC=1 AND gate,
C'=1 NOT gate,
ABC+ AB+ AC'= 1 OR GATE(3 INPUT GATE).
|
using NAND logic, we get:
?
?
results in ________.