Combinational Logic Analysis

Q1:
Implementing the expression using NAND logic, we get:

A (A)

B (B)

C (C)

D (D)

ANS:B - (B)

In option B C NAND D = CD'.

Before OR it is inverted so input to or gate is CD and A' and B'. So that's why o/p= (A'+B'+CD).

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