ANS:E - 52413

"The hotel was not comfortable."

ANS:A - 5

The sizeof function return the given variable. Example: float a=10; sizeof(a) is 4 bytes Step 1: float arr[] = {12.4, 2.3, 4.5, 6.7}; The variable arr is declared as an floating point array and it is initialized with the values. Step 2: printf('%d\n', sizeof(arr)/sizeof(arr[0])); The variable arr has 4 elements. The size of the float variable is 4 bytes. Hence 4 elements x 4 bytes = 16 bytes sizeof(arr[0]) is 4 bytes Hence 16/4 is 4 bytes Hence the output of the program is '4'.

ANS:D - 3 m

The answer should be A. 1/2m.

With ref of Punmia : the second term in slope correction shall be neglected for slopes flatter than about 1 in 25 (i.e slope should be lesser than 0.04).

The slope is Vertical distance/Horizontal distance.
.
Here Vertical distance is h and the horizondal distance is √((L)^2 - (h)^2).

L = 20 given in the problem. We need to find, for which value of h the slope will be less than 0.04.

Sub h = 0.5, we get slope = 0.025;
Sub h = 1, we get slope = 0.050;
Sub h = 2, we get slope = 0.100;
Sub h = 3, we get slope = 0.150; For slopes greater than 5% the above formula must be adopted otherwise the second part of the formula can be neglected.

Since the first three options are less than or equal to 5% they can neglected as the 3m is greater than 5% the second part of formula must included. Hence the answer is (D) 3m. Second term is neglected for slope less than 10%.

Slope for given problem for:

C) (2/20)*100 = 10%.
D) (3/20)*100 = 15%.

So for h = 2 m or less it is neglected.

And for h = 3 m it will be taken into account. For slope greater than 5% closer a closer approximation of corrected slope can be determined by h2/2l + h4/8l3.
Otherwise taken as h2/2l.

In the above example slope taken as 5% of length.
Length = 20 m therefore slope is 1.
Slope = height/length.

We have slope value equal to 1.
Then h2/2l = 1.
Answer is 6.32 m which is more than 3. ** If h is the difference in level between endpoints separated by l, then the slope correction is c=(h^2/2l)+{h^4/8(l^3)}.

** If h is less than 3m in a length often the 20 m, then the quantity h^4/8(l^3) can be neglected. Hence c = h^2/2l.
 

ANS:B - 25 A

.

ANS:A - 1

When the psychrometric ratio is 1, the adiabatic saturation temperature and wet bulb temperature become equal. The psychrometric ratio (ΨΨ) is defined as the ratio of the difference between the enthalpy of the vapor in the air to the difference between the enthalpy of the vapor and the enthalpy of the dry air. Mathematically, it can be expressed as: Ψ=ℎ𝑣−ℎ𝑑𝑎ℎ𝑣−ℎ𝑑Ψ=hv​−hd​hv​−hda​​ Where:

• ℎ𝑣hv​ = specific enthalpy of the vapor in the air
• ℎ𝑑𝑎hda​ = specific enthalpy of the dry air
• ℎ𝑑hd​ = specific enthalpy of the dry air at the wet bulb temperature

ANS:B - not constant along a streamline.

In frictional fluid flow, the quantity vμ\frac{v}{\mu}μv​, where vvv is the velocity of the fluid and μ\muμ is the dynamic viscosity of the fluid, is not constant along a streamline.

Explanation:

1. Dynamic Viscosity (μ\muμ): Dynamic viscosity is a measure of a fluid's resistance to flow under an applied force. It depends on the type of fluid and its temperature.
2. Velocity of the Fluid (vvv): Velocity varies along streamlines in frictional fluid flow, influenced by factors such as pressure gradients, flow obstacles, and boundary conditions.
3. Ratio vμ\frac{v}{\mu}μv​:
   • This ratio vμ\frac{v}{\mu}μv​ is significant because it represents the Reynolds number (ReReRe) for flow. Re=ρvLμRe = \frac{\rho v L}{\mu}Re=μρvL​, where ρ\rhoρ is the density of the fluid and LLL is a characteristic length.
   • ReReRe determines the flow regime (laminar or turbulent). For laminar flow, ReReRe is low, and vμ\frac{v}{\mu}μv​ is relatively constant along streamlines. In turbulent flow, ReReRe is high, and vμ\frac{v}{\mu}μv​ varies significantly.
4. Along a Streamline:
   • Along a streamline in frictional flow, velocity vvv may change due to pressure gradients or external forces, affecting vμ\frac{v}{\mu}μv​.
   • Therefore, vμ\frac{v}{\mu}μv​ is not constant along a streamline because velocity and thus vμ\frac{v}{\mu}μv​ can vary.
5. Conclusion:
   • vμ\frac{v}{\mu}μv​ is a critical parameter in fluid dynamics, influencing flow characteristics and Reynolds number calculations.
   • In summary, vμ\frac{v}{\mu}μv​ is not constant along a streamline in frictional fluid flow, reflecting the dynamic nature of fluid velocity and viscosity interactions.

ANS:B - November 02

The International Day to end impunity for crimes against Journalists is observed every year on November 02.

ANS:B - 30%

The Reserve Bank of India (RBI) has lowered the maximum risk for custodian banks issuing irrevocable payment commitments (IPCs) from 50% to 30%. This decision follows the reduction in trade settlement time from T+2 to T+1 and T+0 for select equities by stock exchanges. The revised guidelines aim to mitigate risks associated with potential downward price movements of equities purchased by foreign institutional investors/mutual funds over two successive days from the trade date.

ANS:C - October 31

World Savings Day 2022 is observed on the 31st of October 2022.

ANS:B - Nagaland

Nagaland government created 3 districts namely Tseminyu, Nuiland and Chumukedima.