What will be the output of the program ?

#include<stdio.h>

int main()
{
    float arr[] = {12.4, 2.3, 4.5, 6.7};
    printf('%d\n', sizeof(arr)/sizeof(arr[0]));
    return 0;
}

ANS:A - 5

The sizeof function return the given variable. Example: float a=10; sizeof(a) is 4 bytes Step 1: float arr[] = {12.4, 2.3, 4.5, 6.7}; The variable arr is declared as an floating point array and it is initialized with the values. Step 2: printf('%d\n', sizeof(arr)/sizeof(arr[0])); The variable arr has 4 elements. The size of the float variable is 4 bytes. Hence 4 elements x 4 bytes = 16 bytes sizeof(arr[0]) is 4 bytes Hence 16/4 is 4 bytes Hence the output of the program is '4'.