Floating Point Issues

Q1: Which of the following statement obtains the remainder on dividing 5.5 by 1.3 ?

A rem = (5.5 % 1.3)

B rem = modf(5.5, 1.3)

C rem = fmod(5.5, 1.3)

D rem = fmod(5.5, 1.3)

Q2: The binary equivalent of 5.375 is

A 101.101110111

B 101.011

C 101011

D None of above

Q3: What are the different types of real data type in C ?

A float, double

B short int, double, long int

C float, double, long double

D double, long int, float

What will you do to treat the constant 3.14 as a long double?

A use 3.14LD

B use 3.14L

C use 3.14DL

D use 3.14LF

Which of the following range is a valid long double (Turbo C in 16 bit DOS OS) ?

A 3.4E-4932 to 1.1E+4932

B 3.4E-4932 to 3.4E+4932

C 1.1E-4932 to 1.1E+4932

D 1.7E-4932 to 1.7E+4932

If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)?
int main()
    float a=5.375;
    char *p;
    int i;
    p = (char*)&a;
    for(i=0; i<=3; i++)
        printf("%02x\n", (unsigned char)p[i]);
    return 0;

A 40 AC 00 00

B 04 CA 00 00

C 00 00 AC 40

D 00 00 CA 04

What will you do to treat the constant 3.14 as a float?

A use float(3.14f)

B use 3.14f

C use f(3.14)

D use (f)(3.14)

Q8: Which statement will you add in the following program to work it correctly?
int main()
    printf('%f\n', log(36.0));
    return 0;

A #include<conio.h>

B #include<math.h>

C #include<stdlib.h>

D #include<dos.h>

We want to round off x, a float, to an int value, The correct way to do is

A y = (int)(x + 0.5)

B y = int(x + 0.5)

C y = (int)x + 0.5

D y = (int)((int)x + 0.5)

A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?




D Depends on big endian or little endian architecture

img not found

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.