1000 kg of sewage contains

ANS:E - both (a) and (c) of above.

1000 kg of sewage contains:

• 0.112 kg in suspension
• 0.112 kg in solution
• 0.225 kg in solution
• 0.450 kg in suspension
• both (a) and (c) of above.

To find out the total amount of material in suspension and in solution, we can sum up the respective masses: Total in suspension = 0.112 kg + 0.450 kg = 0.562 kg Total in solution = 0.112 kg + 0.225 kg = 0.337 kg Now, let's consider the last statement: "both (a) and (c) of above." This implies that we need to consider both the values mentioned in (a) and (c), i.e., 0.112 kg in suspension and 0.225 kg in solution. So, the total amount of material when considering both (a) and (c) is: Total in suspension = 0.112 kg Total in solution = 0.225 kg Therefore, the correct answer considering both (a) and (c) would be 0.112 kg in suspension and 0.225 kg in solution.