Q1: 1000 kg of wet solids are to be dried from 60% to 20% moisture (by weight). The mass of moisture removed in kg is

ANS:C - 400

To find the mass of moisture removed, we need to calculate the initial and final masses of moisture in the wet solids and then find the difference. Given:

• Initial mass of wet solids = 1000 kg
• Initial moisture content = 60% (by weight)
• Final moisture content = 20% (by weight)

1. Calculate Initial and Final Masses of Moisture:
   • Initial mass of moisture = Initial mass of wet solids × Initial moisture content Initial mass of moisture = 1000 kg × 60% = 600 kg
   • Final mass of moisture = Final mass of wet solids × Final moisture content Final mass of moisture = 1000 kg × 20% = 200 kg
2. Calculate the Mass of Moisture Removed: Mass of moisture removed = Initial mass of moisture - Final mass of moisture Mass of moisture removed = 600 kg - 200 kg = 400 kg