Heat Transfer - Engineering

Q1:

1000 kg of wet solids are to be dried from 60% to 20% moisture (by weight). The mass of moisture removed in kg is

A 520

B 200

C 400

D 500

ANS:C - 400

To find the mass of moisture removed, we need to calculate the initial and final masses of moisture in the wet solids and then find the difference. Given:

  • Initial mass of wet solids = 1000 kg
  • Initial moisture content = 60% (by weight)
  • Final moisture content = 20% (by weight)
  1. Calculate Initial and Final Masses of Moisture:
    • Initial mass of moisture = Initial mass of wet solids × Initial moisture content Initial mass of moisture = 1000 kg × 60% = 600 kg
    • Final mass of moisture = Final mass of wet solids × Final moisture content Final mass of moisture = 1000 kg × 20% = 200 kg
  2. Calculate the Mass of Moisture Removed: Mass of moisture removed = Initial mass of moisture - Final mass of moisture Mass of moisture removed = 600 kg - 200 kg = 400 kg
Therefore, the mass of moisture removed is 400 kg.