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Numbers - General Aptitude

Q1:

(112 + 122 + 132 + ... + 202) = ?

A 385

B 2485

C 2870

D 3255

ANS:B - 2485

(112 + 122 + 132 + ... + 202) = (12 + 22 + 32 + ... + 202) - (12 + 22 + 32 + ... + 102)

Ref: (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1)    
6
=  20 x 21 x 41 - 10 x 11 x 21
6 6
= (2870 - 385) = 2485.