Numbers - General Aptitude

Q1:

(12 + 22 + 32 + ... + 102) = ?

A 330

B 345

C 365

D 385

ANS:D - 385

We know that (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1)
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Putting n = 10, required sum = 1 x 10 x 11 x 21 = 385
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