Numbers

(1² + 2² + 3² + ... + 10²) = ?

A 330

B 345

C 365

D 385

ANS:D - 385

We know that (1² + 2² + 3² + ... + n²) =	1	n(n + 1)(2n + 1)
	6

Putting n = 10, required sum =		1	x 10 x 11 x 21		= 385
		6

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