(12 + 22 + 32 + ... + 102) = ?-A-330B-345C-365D-385-D-385

Question

APTITUDE CRACK · Accepted Answer

D 385  We know that (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1) 6 Putting n = 10, required sum = 1 x 10 x 11 x 21 = 385 6

Numbers - General Aptitude