Q1: __________ kg of CaC0₃ on heating will give 56 kg of CaO.

ANS:B - 100

To find out how much CaCO3 (calcium carbonate) is needed to produce 56 kg of CaO (calcium oxide), we need to consider the molar masses and stoichiometry of the reaction. The chemical equation for the thermal decomposition of calcium carbonate is: CaCO3→CaO+CO2CaCO3​→CaO+CO2​ From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO. Given that the molar mass of CaCO3 is approximately 100.09 g/mol100.09g/mol and the molar mass of CaO is approximately 56.08 g/mol56.08g/mol, we can calculate the mass ratio of CaCO3 to CaO: Mass ratio=Molar mass of CaCO3Molar mass of CaO=100.09 g/mol56.08 g/molMass ratio=Molar mass of CaOMolar mass of CaCO3​​=56.08g/mol100.09g/mol​ Mass ratio≈1.783Mass ratio≈1.783 This means that 1.783 grams of CaCO3 produces 1 gram of CaO. To produce 56 kg of CaO, we can use the mass ratio: Mass of CaCO3=Mass ratio×Mass of CaOMass of CaCO3​=Mass ratio×Mass of CaO Mass of CaCO3=1.783×56 kgMass of CaCO3​=1.783×56kg Mass of CaCO3≈99.848 kgMass of CaCO3​≈99.848kg So, approximately 99.848 kg of CaCO3 is needed to produce 56 kg of CaO. Therefore, the closest answer is 100 kg.