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Series-Parallel Circuits - Engineering

Q1:

A 12 k resistor, a 15 k resistor, and a 22 k resistor are in series with two 10 k resistors that are in parallel. The source voltage is 75 V. Current through the 15 k resistor is approximately

A 14 mA

B 1.4 mA

C 5 mA

D 50 mA

ANS:B - 1.4 mA

RT = 12+15+22 = 49.
RT of parallel = (10x10) /10+10) = 5
So, 49+5 =5 4
I = V/R. = 75/54 = 1.388888889 round off so the total current is 1.4 mA.