A 12 kg mass rests on a surface for which the coefficient of friction is μ= 0.15. What is the smallest force that can give the mass acceleration of 3 m/s2 ? (Take g = 10 m/s2).-A-120 NB-100 NC-65 ND-54 N-B-100 N

B 100 N umg 12 * .15 * 10 = 18(f1) f2 = ma =12 * 3 = 36, f1 + f2 = 54.