A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?-A-73.4 and θ = –19.5°B-707 and θ = –19.5°C-2121 and θ = –19.5°D-734 and θ = –38.9°-C-2121 and θ = –19.5°

Question

A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?-A-73.4 and &theta; = &ndash;19.5&deg;B-707 and &theta; = &ndash;19.5&deg;C-2121 and &theta; = &ndash;19.5&deg;D-734 and &theta; = &ndash;38.9&deg;-C-2121 and &theta; = &ndash;19.5&deg;

APTITUDE CRACK · Accepted Answer

C 2121 and &theta; = &ndash;19.5&deg; Xc = 1/2&pi;fC = 707 &Omega; Z = R jXc = 2000 j(707) |z| = sqrt(R*R + Xc*Xc) = 2121 &Omega; Phase angle = arctangent(Xc/R) = 19.5&deg;

RC Circuits - Engineering

A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?

For help Students Orientation
Mcqs Questions

Quick Links

Newsletter

RC Circuits - Engineering

A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?

Solution

For help Students Orientation Mcqs Questions

For help Students Orientation
Mcqs Questions