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RL Circuits - Engineering

Q1:

A 3.3 k resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is

A 8.74 mA

B 874 mA

C 874 A

D 8.74 A

ANS:A - 8.74 mA

R=3.3 = 3300 OHMS.
L=120mH = 0.12H.
f = 2khz = 2000hz.
Source = 12 volt.

XL=2*fl.
2*3.14*2000*0.12/100.
=1507.1ohms.

Z= √R^2+X^2L.
√3300^2+1507.1^2.
√10890000+2271049.
√13161049.
z = 3627.
Z = R * Xc/Z.
z = 3300*1507/3627=1371.1ohms.
Z = V/I or I = V/R.
12/1371=0.00874.
OR 8.75mA.