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Energy and Power - Engineering

Q1:

A 3.3 k resistor dissipates 0.25 W. The current is

A 8.7 mA

B 87 mA

C 8.7 µA

D 8.7 A

ANS:A - 8.7 mA

W = I2R

I = square root(W/R)

= square root( 0.25/(3.3x1000) )

= 0.0087038828

= 8.7 mA