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RL Circuits - Engineering

Q1:

A 470  resistor and a coil with 125  inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is

A 152 mA

B 32 mA

C 12 mA

D 120 mA

ANS:D - 120 mA

You can't just simply calculate Req like 2 resistors in parallel, proper impedance have to be calculated for parallel RL circuit.
I = V/Z.
Z= 1/*(1/R)^2+(1/XL)^2.