Circuit Theorems and Conversions

Q1: A 680  load resistor, RL, is connected across a constant current source of 1.2 A. The internal source resistance, RS, is 12 k. The load current, RL, is

A 0 A

B 1.2 A

C 114 mA

D 1.14 A

ANS:D - 1.14 A

RL = 12 X 10^3 ohms.
r=680 ohms.
I=1.2 A.
Solution
I load=1.2((680/(680+12000)),
I=1.14A.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.