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Applied Mechanics - Engineering

Q1:

A ball of mass 1 kg moving with a velocity of 2 m/sec collides a stationary ball of mass 2 kg and comes to rest after impact. The velocity of the second ball after impact will be

A zero

B 0.5 m/sec

C 1.0 m/sec

D 2.0 m/sec.

ANS:C - 1.0 m/sec

m1v1 = m2v2.

v2 = m1v1/m2,

v2 = 1*2/2 = 1m/sec,

v2 = 1.0m/sec.