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UPSC Civil Service Exam Questions

Q1: A bar of square section is subjected to a pull of 10000 kg. If the maximum allowable shear stress on any section is 500 kg/cm2, then the side of the square section will be

A
5 cm

B
10 cm

C
15 cm

D
20 cm

ANS:B -

10 cm

Tau max = 3/2 * τ(avg).
Tau avg= normal load /area.
Normal load = mac pull/2.
Hence, τ avg =10000/2 * area.
Hence,
500 = 3/2 *(10000/2*area).
Hence area =15
Side=√15.
So, the Answer is C.



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