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UPSC Civil Service Exam Questions - Engineering

Q1:

A bullet of mass 0.01 kg moving with a velocity of 401 m/s strikes a block of mass 4 kg which is free to move in the direction of the bullet, and gets embedded in it. The overall loss of kinetic energy is

A 80.2 Nm

B 401 Nm

C 802 Nm

D 1604 Nm

ANS:C - 802 Nm

Here, v2=0.01*401/(0.01+4)=1 then loss of kinetic energy=0.5*0.01*(401^2-1^2)=804.