Measurements and Instrumentation - Engineering

Q1:

A capacitance transducer has two plates each of area 5 mm2. The coil gap is 2 mm. Displacement sensitivity due to change in gap length is

A 11.1 pF/cm

B 44.2 pF/cm

C 52.3 pF/cm

D 66.3 pF/cm

ANS:A - 11.1 pF/cm

The formula is C = A.ε/D^2.

Where D is the distance between plates, A is area, ε = 8.854*10powerminus12.