Measurements and Instrumentation

Q1: A capacitance transducer has two plates each of area 5 mm2. The coil gap is 2 mm. Displacement sensitivity due to change in gap length is

A 11.1 pF/cm

B 44.2 pF/cm

C 52.3 pF/cm

D 66.3 pF/cm

ANS:A - 11.1 pF/cm

The formula is C = A.ε/D^2.

Where D is the distance between plates, A is area, ε = 8.854*10powerminus12.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.