

Stoichiometry - Engineering
Q1: A car tyre of volume 0.057 m3 is inflated to 300 kPa at 300 K. After the car is driven for 10 hours, the pressure in the tyre increases to 330 kPa. Assume air is an ideal gas and Cv for air is 21 J/mole.K. The change in the internal energy of air in the tyre in J/mole isA 380
B 630
C 760
D 880
ANS:B - 630 To find the change in internal energy of the air in the tire, we can use the first law of thermodynamics, which states that the change in internal energy (Δ𝑈ΔU) of a system is equal to the heat added to the system (𝑄Q) minus the work done by the system (𝑊W). Mathematically, it can be expressed as: Δ𝑈=𝑄−𝑊ΔU=Q−W Since the tire undergoes an adiabatic process (no heat exchange) and work is done due to the change in pressure, we can use the formula for adiabatic work: 𝑊=−𝑃extΔ𝑉W=−PextΔV Where:
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