Download Aptitude Crack
img not found img not found

RLC Circuits and Resonance

Q1: A certain series RLC circuit with a 200 Hz, 15 V ac source has the following values: R = 12 , C = 80 F, and L = 10 mH. The total impedance, expressed in polar form, is

A 12.2812.34° 

B 12.5712.34° 

C 9.9512.34° 

D 12.6212.34° 

ANS:A - 12.2812.34° 

Z=√R^2+(XL-XC)^2
Z=√12^2+((2*PIE*F*L)-(1/2*PIE*F*C))^2
Z=√144+12.566-9.947.

Z=12.28 ohm.

FOR ANGLE θ due to Polar Form as Required,
θ = tangent inverse*(XL-XC/R).
= tan.inv*(12.566-9.947/12).
= 12.31.
So,
= 12.28<12.31* ohm , Option A.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.