Analog Electronics

Q1: A certain transistor has adc of 0.98 and a collectors leakage current of 5 μA. If IE = 1 mA, the base current will be

A 35 μA

B 25 μA

C 15 μA

D 5 μA

ANS:C - 15 μA

Yes, @Srinivas. Here I will give another formula to find the answer.

Ie= (1+beta) Ib;also beta=alpha/1-alpha.
So Ib= (1+beta) /Ie;sub we get 20 microAmpere.



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