A certain transistor has adc of 0.98 and a collectors leakage current of 5 μA. If IE = 1 mA, the base current will be-A-35 μAB-25 μAC-15 μAD-5 μA-C-15 μA

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A certain transistor has adc of 0.98 and a collectors leakage current of 5 &mu;A. If IE = 1 mA, the base current will be-A-35 &mu;AB-25 &mu;AC-15 &mu;AD-5 &mu;A-C-15 &mu;A

APTITUDE CRACK · Accepted Answer

C 15 &mu;A Yes, @Srinivas. Here I will give another formula to find the answer. Ie= (1+beta) Ib;also beta=alpha/1 alpha. So Ib= (1+beta) /Ie;sub we get 20 microAmpere.

Analog Electronics - Engineering

A certain transistor has a_dc of 0.98 and a collectors leakage current of 5 μA. If I_E = 1 mA, the base current will be

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Analog Electronics - Engineering

A certain transistor has adc of 0.98 and a collectors leakage current of 5 μA. If IE = 1 mA, the base current will be

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For help Students Orientation Mcqs Questions

A certain transistor has a_dc of 0.98 and a collectors leakage current of 5 μA. If I_E = 1 mA, the base current will be

For help Students Orientation
Mcqs Questions