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UPSC Civil Service Exam Questions - Engineering

Q1:

A circular plate 100 mm diameter is welded to another plate by means of 6 mm fillet weld. If the permissible shearing stress in the weld equals 10 kg/mm2, then the greatest twisting moment that can be resisted by the weld will be

A 424 π kg.m

B 300 π kg.m

C 212 π kg.m

D 60 π kg.m

ANS:C - 212 π kg.m

T = PD/2.

STRENGTH = P(force) = AREA * STRESS.
P = (0.7s)*πD*10.
P = (0.7*6)*(π100)*10 = 4.2X10^3π .
T = {4.2X10^3π*100}/2 kg-mm
T = 212kg-m.