- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 2
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 27


Networks Analysis and Synthesis - Engineering
Q1: A coil is wound having a diameter d. Its inductance is 10 mH. If it is rewound on the same core with a wire having diameter 0.5 d and total weight of the wire is the same as before, the inductance will beA
5 mH
B
10 mH
C
160 mH
D 40 mH
ANS:C - 160 mH Since diameter is halved, area of cross-section is one-fourth. The number of turns becomes four times. Inductance = μ N2. |


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